Question

(1)+(1+1)+(1+1+1).....(1+1+1+1....n-1) = ?​

Answer 1

Answer:

1+2+3+........+(n-1)=n(n-1)/2

Step-by-step explanation:

we know that 1+2+3+...+n= n(n+1)/2

Replace n by n-1

we get

1+2+3+........+(n-1)=n(n-1)/2

similarly

1+(1+1)+(1+1+1)+......+(1+1+1+...+(n-1))= n(n-1)/2

Answer 2

Answer:

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Step-by-step explanation:

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