Math, asked by sakshiAp, 9 months ago

1+(1+1)+(1+1+1)+......+(1+1.....upto n-1 times)​

Answers

Answered by abhi52329
0

Step-by-step explanation:

Required summation is

1+2+3+4+.....(n-1), which is given by

 \frac{n}{2}  \times (n + 1)

Here we need summation till n-1

hence the answer is

 \frac{(n - 1)}{2}  \times n

Similar questions