√1+√1+√1+√1+ infinite
pls solve
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Answered by
1
Answer:
In your case first term: root(-1)
and the second : -root(-1)
will cut each other and the series will start from third term as -root(-1)..infinity
So like above take -root(-1) common and you get same above thing 1+1+1+1… inf
solve like the same and you get at last and you can also take root of -1 as i (iorta) so
-i(1+1+1+1+1+1+1+1….)
-i(-1/12)
= i/12
hence i/12 is answer
Answered by
0
Answer:
the answer will be infinity
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