Question

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__________ ____ = ___ -_______
SecR - tanR cosR cosR secR +tanR

Answer 1

[tex] \frac{1}{sec R- tan R} + \frac{1}{sec R + tan R} = \frac{1}{cos R} + \frac{1}{cos R} [/tex]

[tex] \frac{sec R+tan R+sec R-tan R}{sec^2 R-tan^2 R} = \frac{2}{cos R} [/tex]

$2sec R = \frac{2}{cos R}$

now both sides are equal to 2 sec R
which satisfies the equation.

Answer 2

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