Question

1 1 1
1. Two chords PQ and PR of a circle are equal. Prove that the bisector of 2 QPR passes through the
2. Two chords AB and CD of a circle with centre at O are produced to meet at M. If OM bise
aº = 20 V3a
AB = BC = CA = 2013 m
Hence, the length of string of each phone is 2013 m.
EXERCISE 10.3
centre of the circle.
- AMC, then prove that AB = CD.
3. If two equal chords AB and CD of a circle intersect within the circle, prove that AD = BC​

Answer 1

Answer:

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