Question

(-1)^1+(-1)^2.........+(-1)^2020=​

Answer 1

Answer:

0

Step-by-step explanation:

let,

odd number=x

even number=y

(-1)^x=-1

(-1)^y=1

(-1)^1+(-1)^2+(-1)^3+(-2)^4.....+(-1)^2019+(-1)^2020

(-1) + 1 + (-1) + 1....+(-1) +1

-1+1-1+1...-1+1

0

Answer 2

Answer:

0 is the answer...

Hope it helps u..