Math, asked by sasaneharshdeep, 13 hours ago

(-1) × (-1) × (-1) × (2m + 1) times,

where m is a natural number, is equal to.​

Answers

Answered by Raziya74774
1

Answer:

m is equal to -0.5 .

Hope you get it

Attachments:
Answered by pulakmath007
3

( - 1) × ( - 1) × ( - 1) × ( 2m + 1 ) times = - 1

where m is a natural number

Given :

( - 1) × ( - 1) × ( - 1) × ( 2m + 1 ) times

where m is a natural number

To find :

The value of the expression

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

( - 1) × ( - 1) × ( - 1) × ( 2m + 1 ) times

where m is a natural number

Step 2 of 2 :

Find the value of the expression

Since m is a natural number

So 2m + 1 is odd

Thus we get

( - 1) × ( - 1) × ( - 1) × ( 2m + 1 ) times

 \sf =  {( - 1)}^{2m + 1}

 \sf =   - 1

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