Question

[1-{1-(1-n)^-1}^-1]^-1 Simplify

Answer 1

Answer:

$[1-\{1-(1-n)^{-1}\}^{-1}]^{-1}=n$

Step-by-step explanation:

Given : Expression $[1-\{1-(1-n)^{-1}\}^{-1}]^{-1}$

To find : Simplify the expression ?

Solution :

Step 1 -  Write the expression,

$[1-\{1-(1-n)^{-1}\}^{-1}]^{-1}$    

Step 2 - Solve the open bracket,

$=[1-\{1-\frac{1}{1-n}}^{-1}]^{-1}$

$=[1-\{\frac{1-n-1}{1-n}}^{-1}]^{-1}$

$=[1-\{\frac{-n}{1-n}}^{-1}]^{-1}$

Step 3 - Solve the curly bracket,

$=[1-\frac{1-n}{-n}]^{-1}$

$=[\frac{n+1-n}{n}]^{-1}$

$=[\frac{1}{n}]^{-1}$

Step 4 - Solve the big bracket,

$=n$

Therefore, $[1-\{1-(1-n)^{-1}\}^{-1}]^{-1}=n$

Answer 2

Answer:

evalute 1-[-1{-1+1×)}]