[1-{1-(1-x^2)^-1}^-1]^-1/2 is equal to. plz solve in detail
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Answered by
96
[1 - { 1- 1/(1-x^2)}^-1]^-1/2
=[1 - { 1- x^2 -1/(1-x^2) }^-1]^-1/2 here we used a^-n = 1/a^n
= [1 - {(-x^2)/(1-x^2)}^-1]^-1/2
= [ 1 - { x^2 /( x^2 -1) }^-1]^-1/2
= [ 1- (x^2-1)/ x^2]^-1/2
= [ (x^2 -x^2+1)/ x^2]^-1/2
= [1/x^2]^-1/2
= [x^2]^1/2
= x ^2*1/2
= x
=[1 - { 1- x^2 -1/(1-x^2) }^-1]^-1/2 here we used a^-n = 1/a^n
= [1 - {(-x^2)/(1-x^2)}^-1]^-1/2
= [ 1 - { x^2 /( x^2 -1) }^-1]^-1/2
= [ 1- (x^2-1)/ x^2]^-1/2
= [ (x^2 -x^2+1)/ x^2]^-1/2
= [1/x^2]^-1/2
= [x^2]^1/2
= x ^2*1/2
= x
Answered by
30
Answer:
x
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