Question

[1-{1-(1-x^2to)^-1}^-1]^-1/2 is equal ​

Answer 1

Answer:

Step-by-step explanation:

2x-7/2

[1-(1-(1–2x)-1)-1]-1/2=

1–(1+(-1(1–2x)-1)-1]-1/2=

1–1–1+2x-1–1-(1/2)=

(1–1–1)+2x-(1+1)-1/2=

-1+2x-2–1/2=

-1(1+2)+2x-1/2=

-3+2x-1/2=

-1(3+1/2)+2x=

-1(6/2+1/2)+2x=

-7/2+2x=

2x-7/2

C.H.

mark me the brainiest

Answer 2

Step-by-step explanation:

[1-{1-(1-x^2)^-1}^-1]^-1/2

[1-{1-1/1-x^2-1}^-1]^-1/2

[1-{1/1-x^2}^-1]^-1/2

[1-1-x^2]^-1/2

2√1/x^2