Question

1,1=11 2,2=21 3,3=31 4,4=41 then 6,3=?

Answer 1

$Given \: 1,1=11\: 2,2=21\: 3,3=31\: 4,4=41$

/* Observe the sequence, we can find following

pattern */

$\boxed{ \pink{ a,b= 5 \times (a+b) + 1}}$

$i) 1,1 \\= 5( 1+ 1 ) + 1\\= 5\times 2 + 1 \\= 10 + 1 \\= 11$

$ii) 2,2 \\= 5( 2 + 2 ) + 1\\= 5\times 4 + 1 \\= 20 + 1 \\= 21$

$iii) 3,3 \\= 5( 3+ 3 ) + 1\\= 5\times 6 + 1 \\= 30 + 1 \\= 31$

$iv) 4,4 \\= 5( 4+ 4) + 1\\= 5\times 8 + 1 \\= 40 + 1 \\= 41$

$Now ,\red{6,3} \\= 5( 6+3 ) + 1\\= 5\times 9 + 1 \\= 45 + 1 \\= 46$

Therefore.,

$\red{ 6,3 } \green { = 46 }$

•••♪

Answer 2

Observe the sequence, we can find following

pattern */

\boxed{ \pink{ a,b= 5 \times (a+b) + 1}}

a,b=5×(a+b)+1

\begin{gathered}i) 1,1 \\= 5( 1+ 1 ) + 1\\= 5\times 2 + 1 \\= 10 + 1 \\= 11\end{gathered}

i)1,1

=5(1+1)+1

=5×2+1

=10+1

=11

\begin{gathered}ii) 2,2 \\= 5( 2 + 2 ) + 1\\= 5\times 4 + 1 \\= 20 + 1 \\= 21\end{gathered}

ii)2,2

=5(2+2)+1

=5×4+1

=20+1

=21