Math, asked by vishnuvaishnavi727, 10 months ago

1+1=121, 1+2=134, 2+2=444, 3+2=954, then 3+3= ?

Answers

Answered by riyaharyanvi
71
HEY USER ,

HERE IS YOUR ANSWER :-

1+1 = 121

1+2 = 134

2+2 = 444

3+2 = 954

3+3 = 969

Step by step explanation :-

1) multiply the first number by itself .

2) add first and second number .

3) again multiply second number by itself .

4) finally , write the resulted number.

So , here the first number is 3 and second number is 3 .

1) 3×3 = 9
2) 3+3 = 6
3) 3×3 = 9
= 969

HOpE iT HELPS YOU !!!!.....✌️✌️✌️

rishy12: wahh
vishnuvaishnavi727: thank u ji
riyaharyanvi: wlcm
Answered by HanitaHImesh
6

Given,

1+1 = 121

1+2 = 134

2+2 = 444

3+2 = 954

To find,

The value of 3+3.

Solution,

We can easily solve this numerical problem by following the given process.

Now,

After carefully observing the pattern of the given sequence, it can be said that the first digit of the three-digit sequence is the multiplication of the first number with itself, the second digit is the addition of the first and second number, and the third digit is the multiplication of the second number with itself.

So,

For 3+3,

The first digit will be 3×3 = 9.

The second digit will be 3+3 = 6

The third digit will be 3×3 = 9.

Then,

The number will be 969.

Hence, the value of 3+3 will be 969.

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