Question

1+1=141,1+2=164,2+2=484,2+3=4109,3+3=?

Answer 1

9129.............

★The logic is a+b = [a²][2(a+b)][b²]

Verification: 1+1 = [1²][2(1+1)][1²] = [1][4][1] = 141

Similarly, 2+3 = [2²][2(2+3)][3²] = [4][10][9] = 4109

Thus, 3+3 = [3²][2(3+3)][3²] = [9][12][9] = 9129

Answer 2

Answer:

9129

Step-by-step explanation:

as we can see,

here

1+1=141

middle term comes by multiplying 2 to the original sum and the first and last term are squares of their corresponding numbers

1+1=(1)²2*(1+1)(1)²

similarly,

3+3=(3)²2*(3+3)(3)²

=9129