1/(1+√2)+1/(√2+√3)+1/(√3+√4)+1/(√4+√5)+1/(√5+√6)+1/(√6+√7)+1/(√7+√8)+1/(√8+√9)
Answers
Answered by
5
i think u can understand this, we changed denominator terms
since a+b=b+a
since a+b=b+a
Attachments:
bhattisingh111:
Thanks
Similar questions