Math, asked by akshyap, 1 year ago

[1/1*2+1/2*3+1/3*4+.......+1/99*100]=?​

Answers

Answered by gautamkumar118
6

Answer:

Given, 1/1 * 2 + 1/2 * 3 + 1/3 * 4 ..… + 1/99 * 100

Evaluate the equation with (1/x)-(1/(x+1).

= 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 … + 1/99 - 1/100

= 1 -1/100

= 99/100.

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