Question

1/1*2+1/2*3+1/3*4+...+1/n(n+1)​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

let

f(n)=1/(1x2)+1/(2x3)+1/(3x4)...+1/(n(n+1)).

The first thing we notice is that for n > 1, we are just adding another fraction to the previous value of f(n). So we can construct f(n) = f(n-1) + 1/(n(n+1)).

Now look at the small values of n:

f(1) = 1/2,

f(2) = 1/2 + 1/6 = 2/3,

f(3) = 2/3 + 1/12 = 3/4,

f(4) = 3/4 + 1/20 = 4/5, etc.

So for the first few small values of n, we have proven by demonstration that f(n) = n / (n+1).

Our task is to prove that if it works for any positive integer value of n, then it works for n + 1. This way, it must by induction work for all subsequent values of n.

Formally said, we need to prove that if for some positive integer n we can show that f(n) = n / (n+1), then we can conclude that f(n+1) = (n + 1) / (n + 2).

We begin the real "proof" by expanding f(n + 1):

f(n + 1) = f(n) + 1 / ((n+1)((n+1)+1)) because that's based on the construction.

= n / (n+1) + 1 / ((n+1)(n+2)) because f(n) = n / (n+1); this is called "using what you know from earlier".

= n(n+2) / ((n+1)(n+2)) + 1 / ((n+1)(n+2)) because we can multiply the left fraction by (n+2)/(n+2).

= (n2 + 2n + 1) / ((n+1)(n+2)) because we have a common denominator and can combine the numerators.

= (n+1)2 / ( (n+1)(n+2)) because we can factor the numerator now; it is a perfect square.

= (n+1) / (n+2) because we can cancel the common (n+1) factor from the numerator and denominator.