Math, asked by ItzGucciGirl, 9 days ago

1/(1 ? 2) + 1/(2 ? 3) + 1/(3 ? 4) + ….. + 1/{n(n + 1)} = ?​

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Answers

Answered by vikkiain
1

Answer:

 \frac{n}{n + 1}

Step-by-step explanation:

  \frac{1}{1}  -  \frac{1}{2}  =   \frac{1}{1 \times 2} \\  \frac{1}{2}  -  \frac{1}{3}  =  \frac{1}{2 \times 3}  \\  \frac{1}{3}  -  \frac{1}{4}  =  \frac{1}{3 \times 4} \\ . \\ . \\ . \\ sum \: of \: all \\  \frac{1}{n}  -  \frac{1}{n + 1}  =  \frac{1}{n( n+ 1)}  \\  \frac{1}{1}  -  \frac{1}{n + 1}  =  \frac{1}{1 \times 2}  +  \frac{1}{2 \times 3}  +  \frac{1}{3 \times 4}  + ... +  \frac{n}{n + 1}  \\  \frac{n}{ n+ 1} .

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