Question

1.(×+1)²=2(×-3)
2.ײ-2×=(-2)(3-×)
3.(×-2)²(×+1)=(×-1)(×+3)

Answer 1

Answer:

Here's your answer in the attachment

Answer 2

Answer:

(x+1)^2 = 2(x-3)

x^2+2x = 2x - 6

x^2 = -6-1

x^2 = -7

x = -7 root

x^2 - 2x = (-2)(3-x)

x^2 - 2x = -6 + 2x

x^2 - 2x - 2x = -6

x^2 - 4x = -6

4x (x-1) = -6

(x - 2)^2 (x + 1) = (x - 1) (x+3)

(x^2 + 4 + 4x ) (x+1) = x^2 + 3x - x - 3

(x^3 + 4 +4x^2 + x^2 + 4 + 4x = x^2 + 2x -

x^3 + 4x^2 + 6x + 7 =0

Step-by-step explanation:

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