Question

(1) 1 : 2
(2) 3 : 28
(3) 4 : 65
(4) 2 : 7

Which term does NOT belong with others?​

Answer 1

$\huge{ \underline{ \rm{ \red{Answer...}}}}$

The above question is based on number analogy and we have to find the odd one out of the 4 given pairs. So, firstly we have find the logic behind the question. Finding logic can be practised by solving more and more questions like these. This will increase speed and accuracy.

$\Large{ \underline{ \rm{ \red{Logic...}}}}$

Here, In this question, observe the pattern:

$\large{ \boxed{ \rm{2nd \: number = {(1st \: number)}^{3} + 1}}}$

By using this logic, let's find out which one of the given pair is odd pair.

$\Large{ \underline{ \rm{ \red{Solution...}}}}$

Here,

$\large{ \ast \: { \rm{2 = {1}^{3} + 1}}} \\ \\ \large{ \ast \: { \rm{28 = {3}^{3} + 1}}} \\ \\ \large{ \ast \: { \rm{65 = {4}^{3} + 1}}} \\ \\ \large{ \ast \: { \rm{7 \neq \: {2}^{3} + 1 \: \red{\longrightarrow \: odd \: pair}}}}$

Because 2^3 + 1 = 9, hence the last pair is odd.

$\Large{\cdot{\underline{\purple{\rm{Option \: D}}}}}$

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Answer 2

$\huge\bigstar\blue{Answer}$

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• 1 : 2 => ( 1 )³ + 2 => 1 + 2 = 3

• 3 : 28 => ( 3 )³ + 1 => 27 + 1 => 28

• 4 : 65 => ( 4 )³ + 1 => 64 + 1 => 65

• 2 : 7 => ( 2 )³ + 1 => 8 + 1 => 9 ( 9 ≠ 7 )

Hence, 4th term is odd

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