1
1
+
= 2secA
1+ sinA 1 - sin A
Answers
Answered by
4
Answer:
L.H.S.
1+sinAcosA+cosA1+sinA
=cosA(1+sinA)cos2A+(1+sinA)2
=cosA(1+sinA)cos2A+1+sin2A+2sinA
=cosA(1+sinA)2+2sinA
=cosA2=2secA = R.H.S.
Answered by
47
LHS =cosA/(1+sinA) +(1+sinA)/cosA
={cos A +(1+sinA)³ycosA.(1+sinA)
={cos A+1+sin A+2sinAy/cosA.(1+sinA)
use sin?Ø +cos?0 =1
=(1+1+2sinA)/cosA(1+sinA)
=2(1+sinA)/cosA(1+sinA)
=2/COSA
=2secA = RHS
Similar questions
Hindi,
1 month ago
Social Sciences,
1 month ago
English,
1 month ago
Math,
3 months ago
History,
3 months ago