Math, asked by mahadihasan51150, 3 months ago

1
1
+
= 2secA
1+ sinA 1 - sin A​

Answers

Answered by Anonymous
4

Answer:

L.H.S.

1+sinAcosA+cosA1+sinA

=cosA(1+sinA)cos2A+(1+sinA)2

=cosA(1+sinA)cos2A+1+sin2A+2sinA

=cosA(1+sinA)2+2sinA

=cosA2=2secA = R.H.S.

Answered by Anonymous
47

LHS =cosA/(1+sinA) +(1+sinA)/cosA

={cos A +(1+sinA)³ycosA.(1+sinA)

={cos A+1+sin A+2sinAy/cosA.(1+sinA)

use sin?Ø +cos?0 =1

=(1+1+2sinA)/cosA(1+sinA)

=2(1+sinA)/cosA(1+sinA)

=2/COSA

=2secA = RHS

Similar questions