1/√1+√3+1/√3+√5+1/√5+√7+..... Upto n terms,is equal to
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N'th term is 1 / √2n-1+√2n+1.
On rationalizing we get
√2n+1-√2n+-1 / 2
We can write it as √2n+1/ 2 - √2n-1 / 2
Star puting values in the above eq.
Tema will start canceling out and we get
√2n+1 / 2 - 1/2
= 1/2 {(√2n+1)-1}
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