Question

1.1/3(6x+24)=-1/4(12x-72)+20
2.5/6x+3/8x=2+1/3x


SOLVE THIS LINEAR EQUATIONS. GIVEN UP.

Answer 1

1) L.H.S = 1*1/3(6x+24) = 2x+8         ----------- eq.1
    R.H.S = -1/4(12x-72)+20 = -3x+38  -----------eq.2
Now equate L.H.S and R.H.S
   2x+8 = - 3x+38
2x+3x = 38-8
    5x   = 30
      x   =  30/5
      x   =   6

Answer 2

1.
$\frac{1}{3}(6x+24)= \frac{-1}{4} (12x-72)+20$

⇒$\frac{1}{3}*6x+ \frac{1}{3}*24= \frac{-1}{4}*12x- \frac{-1}{4}*(-72) +20$

⇒$2x + 8 = -3x+18+20$
⇒$2x+3x=18+20-8$
⇒$5x=30$
⇒$x= \frac{30}{5}=6$

2.
$\frac{5}{6x} + \frac{3}{8x} =2+ \frac{1}{3x}$

⇒$\frac{20+9}{24x} = \frac{6x+1}{3x}$

⇒$\frac{29}{24x} = \frac{6x+1}{3x}$

⇒$3x*29=24x*(6x+1)$
⇒$87x=144 x^{2} +24x$
⇒$87x-24x=144 x^{2}$
⇒$63x=144x^{2}$

⇒ $x= \frac{63}{144}$

$x \neq 0$ as the denominator can't be zero.