1 + 1 = 3 how its have an answer ........... answer for being brainlist
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Answered by
1
K now this question has become a common one......
Let
a=b
Multiply both sides by b,
ab=b^2
Subtract a^2 from both sides and factorize:
ab-a^2=b^2-a^2
a(b-a)=(b+a)(b-a)
Simplify and add 1 to both sides:
a=b+a
a+1=b+a+1
Now since a=b (the starting point of this proof), we can write this as:
a+1=a+a+1
a+1=2a+1
And in the case where a=1, we have:
1+1=2+1
So, therefore,
1+1=3
Let
a=b
Multiply both sides by b,
ab=b^2
Subtract a^2 from both sides and factorize:
ab-a^2=b^2-a^2
a(b-a)=(b+a)(b-a)
Simplify and add 1 to both sides:
a=b+a
a+1=b+a+1
Now since a=b (the starting point of this proof), we can write this as:
a+1=a+a+1
a+1=2a+1
And in the case where a=1, we have:
1+1=2+1
So, therefore,
1+1=3
evi1iay:
Lol I for got it
Answered by
0
Ok
Assume that
A=b
Multiply both side with b
Ab=b^2
Add with b^2
Ab+b^2=b^2+b^2
Take b.common
B(a+b)=B(b+b) [actually I should cancel them but no I want 1+1=3]
A+b=b+b
Let’s subtract 1 to them on both sides
1-(a+b)=1-(b+b)
Let’s take a= 1
1-(1+1)=1-(1+1) [ we took a=b]
1-(2)=1-(2)
-1+(2)+1-(2)=0
OMG I can’t do it f_uck this I’m out
Assume that
A=b
Multiply both side with b
Ab=b^2
Add with b^2
Ab+b^2=b^2+b^2
Take b.common
B(a+b)=B(b+b) [actually I should cancel them but no I want 1+1=3]
A+b=b+b
Let’s subtract 1 to them on both sides
1-(a+b)=1-(b+b)
Let’s take a= 1
1-(1+1)=1-(1+1) [ we took a=b]
1-(2)=1-(2)
-1+(2)+1-(2)=0
OMG I can’t do it f_uck this I’m out
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