Question

1-1/3 log 10^64 solve this equatio

Answer 1

$\huge\bf{Answer:-}$

Refer the attachment.

Answer 2

Question :------

we have to find value of (1 - 1/3log(base10)64) ?

Formula used :-----

• nlog(a) = log(a)^n
• (a^m)^n = a^mn
• log(base10)4 = 0.602

solution :----------

$1 - \frac{1}{3} log_{10}(64) \\ \\ 1 - log_{10}(64)^{ \frac{1}{3} } \\ \\ 1 - log_{10}( {4}^{3} )^{ \frac{1}{3} } \\ \\ 1 - log_{10}( {4}^{3 \times \frac{1}{3} } ) \\ \\ 1 - log_{10}(4) \\ \\ 1 - 0.602 \: \\ \\ = 0.398$

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● $\orange{\bold{Product\:Rule\:Law:}}$

loga (MN) = loga M + loga N

● $\pink{\bold{Quotient\:Rule\:Law:}}$

loga (M/N) = loga M - loga N

● $\green{\bold{Power\:Rule\:Law:}}$

IogaM^(n) = n Ioga M