Math, asked by munir19560, 7 months ago

1. 1÷3(x-3
)+2÷3=1÷3 (4x-3)+7÷2
2.The sum of fi've consecutive number is 45
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Answers

Answered by niranjan1739
1

Step-by-step explanation:

Let the four consecutive numbers be x,x+1,x+2 and x+3.

Therefore, x+x+1+x+2+x+3=38

4x+6=38

4x=38−6

4x=32 (Divide both sides by 4)

x=8

So, the second number is 9.

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Answered by karan44152
0

Step-by-step explanation:

x+(x+1)+(x+2)+(x+3)+(x+4)=45

5x+10=45

5x=45-10

5x=35

x=7

x+1=7+1=8

x+2=7+2=9

x+3=7+3=10

x+4=7+4=11

7,8,9,10,11 are five consecutive number

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