Question

1. -1\4{3\4(-3\4+1\2) 2\8}
2. (3\4-8\2) 2\3+4\8-2\3
3. 1\4{2\4(3\4+5\8) -1\4}-1\8
please answer fast​

Answer 1

Answer:

$1. \: \frac{ - 1}{4} \times ( \frac{3}{4} \times ( \frac{ - 3}{4} + \frac{1}{2} ) \times \frac{2}{8} ) = \frac{3}{256} \\ 2. \: (\frac{3}{4} - \frac{8}{2} ) \times \frac{2}{3} + \frac{4}{8} - \frac{2}{3} = \frac{ - 7}{3} \\ 3. \: \frac{1}{4} \times ( \frac{2}{4} \times ( \frac{3}{4} + \frac{5}{8} ) - \frac{1}{4} ) - \frac{1}{8} = \frac{ - 1}{64}$

Step-by-step explanation:

$Given, \\ 1. \: \frac{ - 1}{4} \times ( \frac{3}{4} \times ( \frac{ - 3}{4} + \frac{1}{2} ) \times \frac{2}{8} ) \\ = \frac{ - 1}{4} \times ( \frac{3}{4} \times ( \frac{ - 3 + 2}{4} ) \times \frac{2}{8} ) \\ = \frac{ - 1}{4} \times ( \frac{3}{4} \times ( \frac{ - 1}{4} ) \times \frac{2}{8} ) \\ = \frac{ - 1}{4} \times \frac{3}{4} \times \frac{ - 1}{4} \times \frac{2}{8} \\ = \frac{6}{512} \\ = \frac{3}{256} \\ 2. \: (\frac{3}{4} - \frac{8}{2} ) \times \frac{2}{3} + \frac{4}{8} - \frac{2}{3} \\ = ( \frac{3 - 16}{4} ) \times \frac{2}{3} + \frac{4}{8} - \frac{2}{3} \\ = ( \frac{ - 13}{4} ) \times \frac{2}{3} + \frac{4}{8} - \frac{2}{3} \\ = \frac{ - 13}{6} + \frac{4}{8} - \frac{2}{3} \\ = \frac{( - 13 \times 4) + (4 \times 3)}{24} - \frac{2}{3} \\ = \frac{ - 52 + 12}{24} - \frac{2}{3} \\ = \frac{ - 40}{24} - \frac{2}{3} \\ = \frac{ - 40 - 16}{24} \\ = \frac{ - 56}{24} \\ = \frac{ - 7}{3} \\ 3. \: \frac{1}{4} \times ( \frac{2}{4} \times ( \frac{3}{4} + \frac{5}{8} ) - \frac{1}{4} ) - \frac{1}{8} \\ = \frac{1}{4} \times ( \frac{2}{4} \times ( \frac{(3 \times 6) + (5 \times 3)}{24} ) - \frac{1}{4} ) - \frac{1}{8} \\ = \frac{1}{4} \times ( \frac{2}{4} \times \frac{33}{24} - \frac{1}{4} ) - \frac{1}{8} \\ = \frac{1}{4} \times ( \frac{33}{48} - \frac{1}{4} ) - \frac{1}{8} \\ = \frac{1}{4} \times ( \frac{33 - 12}{48} ) - \frac{1}{8} \\ = \frac{1}{4} \times \frac{21}{48} - \frac{1}{8} \\ = \frac{21}{192} - \frac{1}{8} \\ = \frac{21 - 24}{192} \\ = \frac{ - 3}{192} \\ = \frac{ - 1}{64}$

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