1
___________
(1 + √5 + √3)
rastionalise the denomination
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(1+√5+√3)
= 1.
(1+√5)+√3
= 1{(1+√5)-√3}
(1+√5)²-√3²
= 1{(1+√5)-√3}
1+5+2√5-3
= (1+√5)-√3
2√5+3
= {(1+√5)-√3}(2√5-3)
2√5²-3²
=2√5-3+10-3√5-2√15+3√3
20-9
= -√5+10-2√15+3√3
-√5+10-2√15+3√3 11
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