Question

(1/1+a^ m-n) + (1/1+a^n-m)
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Answer 1

Answer:

1+a^m-n+1+a^m-n

=2+a^m-n+a^-(m-n)

=2+a^m-n-a^m-n

=2

Answer 2

Answer:

GIVEN [1 / 1+a^(n-m)] + [1 / 1+a^(m-n)]

=[1/1+(a^n/a^m)]+[1/1+(a^m/a^n)]

=[1/(a^m+a^n/a^m)]+[1/(a^n+a^m/a^n)]

=[a^m/(a^m+a^n)]+[a^n/(a^n+a^m)]

=[a^m+a^n]/[a^m+a^n]

=1

so answer is 2