Question

1/1+a^n-m + 1/1+a^m-n​

Answer 1

Step-by-step explanation:

$\frac{1}{ 1 + {a}^{n - m}}+ \frac{1}{ 1 + {a}^{m - n} } = > \frac{1 + {a}^{n - m} + 1 + {a}^{m - n}} {(1 + {a}^{n - m})(1 + {a}^{m - n})}$

$= > \frac{2 + a^{n - m} + a^{m - n} }{1 + {a}^{n - m} + {a}^{m - n} + {a}^{n - m + m - n} } = >$

$\frac{2 + {a}^{m - n} + {a}^{n - m} }{1 + {a}^0 + {a}^{m - n} + {a}^{n - m}} = > \frac{2 + {a}^{m - n} + {a}^{n - m} }{2 + {a}^{m - n} + {a}^{n - m}} = > 1$

Hope it helps you.