1/[1+a^(n-m)]+1/[1+a^(m-n)] .... please help guys
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Answer:
GIVEN [1 / 1+a^(n-m)] + [1 / 1+a^(m-n)]
=[1/1+(a^n/a^m)]+[1/1+(a^m/a^n)]
=[1/(a^m+a^n/a^m)]+[1/(a^n+a^m/a^n)]
=[a^m/(a^m+a^n)]+[a^n/(a^n+a^m)]
=[a^m+a^n]/[a^m+a^n]
=1
so answer is 2
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Answer:
1
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