Question

1/1+a raise to m-n + 1/1+a raise to n-m

Answer 1

Answer:

GIVEN [1 / 1+a^(n-m)] + [1 / 1+a^(m-n)]

=[1/1+(a^n/a^m)]+[1/1+(a^m/a^n)]

=[1/(a^m+a^n/a^m)]+[1/(a^n+a^m/a^n)]

=[a^m/(a^m+a^n)]+[a^n/(a^n+a^m)]

=[a^m+a^n]/[a^m+a^n]

=1

so answer is 2