Question

1.1 A travelling wave moving from left to right has an amplitude of 0.15 m, a frequency of 550Hz and a wavelength of 0.01 m. Deduce an equation describing the wave

Answer 1

Dear Student,

◆ Answer -

y = 0.15sin2π(550/t-x/0.01) m

● Explanation -

We'll interpret given data one by one.

• Left to right => +ve sign
• Amplitude => a = 0.15 m
• Frequency => f = 550 Hz
• Wavelength => λ = 0.01 m

Standard form of equation of travelling wave is y = a.sin2π(f/t-x/λ).

So substituting the values, eqn of wave becomes y = 0.15sin2π(550/t-x/0.01) m.

Thanks dear...