Question

1
1 Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height
is 6. Find the ratio of areas of these triangles.​

Answer 1

Answer:

$\frac{1}{2} \times b \times h$

1st triangle

$\frac{1}{2} \times 9 \times 5 = \frac{45}{2}$

2nd triangle

$\frac{1}{2} \times 10 \times 6 = \frac{60}{2}$

now the ratio

$\frac{45}{2} \div \frac{60}{2} \\ = \frac{45}{2} \times \frac{2}{60}$

$\frac{45}{60} = \frac{15}{20} = \frac{3}{4}$

therefore the ratio = 3:4

hope it helps

Answer 2

Answer:

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given:

BC = 9, AB = 5, PQ = 6 and QR = 10.

∴A(△ABC)/A(△PQR)

=AB×BC/PQ×QR

=5×9/6×10

=3/4