1.1 cm cube of copper is to be drawn into a cylindrical wire of 0.5 CM in diameter calculate the length of the wire
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7
Solution:-
Let the length of the wire be 'h' cm
1 dm = 10 cm
Volume of metal = 2.2 dm³ = 2.2(10 cm)³
= 2.2*1000
Volume of metal = 2200 cm³
Let 'r' be the radius of the cylinder.
Given : Diameter = 0.25 cm
So, r = 0.25/2
r = 0.125 cm
Volume of metal in the wire = 2200 cm³
∴ πr²h = 2200 cm³
⇒ 22/7*(0.125)²*h = 2200
⇒ h = (2200*7)/22*0.015625
⇒ h = 15400/0.34375
h = 44800 cm
Or 44800/10
Height = 4480 dm
Answer.
Let the length of the wire be 'h' cm
1 dm = 10 cm
Volume of metal = 2.2 dm³ = 2.2(10 cm)³
= 2.2*1000
Volume of metal = 2200 cm³
Let 'r' be the radius of the cylinder.
Given : Diameter = 0.25 cm
So, r = 0.25/2
r = 0.125 cm
Volume of metal in the wire = 2200 cm³
∴ πr²h = 2200 cm³
⇒ 22/7*(0.125)²*h = 2200
⇒ h = (2200*7)/22*0.015625
⇒ h = 15400/0.34375
h = 44800 cm
Or 44800/10
Height = 4480 dm
Answer.
sakshi8918:
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Answered by
6
Volume of cube = a³ = 1.1³ = 1.331 = 1331/1000 cm³
Volume of cylinder = πr²h
1331/1000 = 22/7×0.5×0.5×h
1331/1000×7/22×2×2 = h
H = 1.69. cm
Volume of cylinder = πr²h
1331/1000 = 22/7×0.5×0.5×h
1331/1000×7/22×2×2 = h
H = 1.69. cm
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