1.1 cm3 of gold is drawn into the wire of 0.1mm in diameter. Find the length of the wire in meter.
Answers
Answered by
70
Given:
Volume of gold = 1.1 cm³
Volume of gold = 1.1 × 1000 mm³ = 1100mm³
[ 1cm³ = 1000 mm³]
Diameter of the wire = 0.1mm
Radius= Diameter/2 = 0.1 /2 =0.05 mm
Let the length of a wire h mm.
Volume of wire (Cylinder) = πr²h
Volume of gold = Volume of wire
[Volume of gold is melted and drawn into a wire of diameter 0.1 mm]
1100 = 22/7 × (0.05)²× h
1100= 22/7× 0.05 × 0.05 × h
h = (1100 × 7) / (22× 0.05 × 0.05)
h = 7700 / 22 ×0 .0025
h = 77000000/ 550= 140000 mm
h = 140000/1000 = 140m
[ 1 mm = 1/1000 m]
Hence, the length of the wire= 140 m
HOPE THIS WILL HELP YOU....
Volume of gold = 1.1 cm³
Volume of gold = 1.1 × 1000 mm³ = 1100mm³
[ 1cm³ = 1000 mm³]
Diameter of the wire = 0.1mm
Radius= Diameter/2 = 0.1 /2 =0.05 mm
Let the length of a wire h mm.
Volume of wire (Cylinder) = πr²h
Volume of gold = Volume of wire
[Volume of gold is melted and drawn into a wire of diameter 0.1 mm]
1100 = 22/7 × (0.05)²× h
1100= 22/7× 0.05 × 0.05 × h
h = (1100 × 7) / (22× 0.05 × 0.05)
h = 7700 / 22 ×0 .0025
h = 77000000/ 550= 140000 mm
h = 140000/1000 = 140m
[ 1 mm = 1/1000 m]
Hence, the length of the wire= 140 m
HOPE THIS WILL HELP YOU....
Answered by
5
Answer:
Volume of gold = 1.1 cm³
Volume of gold = 1.1 × 1000 mm³ = 1100mm³
( 1cm³ = 1000 mm³)
Diameter of the wire = 0.1mm
Radius= Diameter/2 = 0.1 /2 =0.05 mm
Let the length of a wire h mm.
Volume of wire (Cylinder) = πr²h
Volume of gold = Volume of wire
(Volume of gold is melted and drawn into a wire of diameter 0.1 mm)
1100 = 22/7 × (0.05)²× h
1100= 22/7× 0.05 × 0.05 × h
h = (1100 × 7) / (22× 0.05 × 0.05)
h = 7700 / 22 ×0 .0025
h = 77000000/ 550= 140000 mm
h = 140000/1000 = 140m
( 1 mm = 1/1000 m)
Hence, the length of the wire= 140 m
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