Math, asked by achyutsri2006, 1 day ago

1+1+cot^2A+1+tan^2A+4

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Answered by Aadhav1234

2

Answer:

We have

LHS =(1+1tan2A)(1+1cot2A)

=(1+cot2A)(1+tan2A)=cosec2A⋅sec2A

=1sin2A⋅1cos2A=1sin2Acos2A

=1sin2A(1−sin2A)=1(sin2A−sin4A)=RHS.

∴LHS=RHS.

Step-by-step explanation:

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