Question

1, 1 find a quadratic polynomial each when the given number as the sum as protect zero respectively
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Answer 1

Answer:

Product of zeros =αβ=2×3=6. Thus when α=2 and β=3 the sum and product of zero's are 5 and 6. Thus we can split the 2nd term of a quadratic polynomial x2−5x+6=0.

Answer 2

Answer:

(i)1/4, -1

(i)1/4, -1Now formula of quadratic equation is

(i)1/4, -1Now formula of quadratic equation isx²-(Sum of root)x + (Product of root) = 0

(i)1/4, -1Now formula of quadratic equation isx²-(Sum of root)x + (Product of root) = 0Plug the value in formula we get

(i)1/4, -1Now formula of quadratic equation isx²-(Sum of root)x + (Product of root) = 0Plug the value in formula we getx² –(1/4)x -1 = 0

(i)1/4, -1Now formula of quadratic equation isx²-(Sum of root)x + (Product of root) = 0Plug the value in formula we getx² –(1/4)x -1 = 0Multiply by 4 to remove denominator we get

(i)1/4, -1Now formula of quadratic equation isx²-(Sum of root)x + (Product of root) = 0Plug the value in formula we getx² –(1/4)x -1 = 0Multiply by 4 to remove denominator we get4x² - x -4 = 0

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brainlaistfind a quadratic polynomial each when the given number as the sum as protect zero respectively