Question

1
1. Find f (0), f(-1) and f
for each of the following polynomials :
2
(i) f (x) = 12x - 3x2 - 4
(ii) f (t) = (t + 1) (t - 2) (2t - 1)​

Answer 1

f(0)=12(0)-3(0)^2-4

0 -0-4

-4

f(-1) = 12(-1)-3(-1)^2-4

-12-3-4

-19

f(1/2)= 12(1/2)-3(1/2)^2-4

6- 3(1/4)-4

6/1-3/4-4/1

24/4-3/4-16/4

5/4

f(t) = (t+1)(t-2)(2t-1)

f(0) =(0+1)(0-2)(2(0)-1)

1-2-1

-2

f(-1) = (-1+1)(-1-2)+(2(-1)-1)

0-3-3

-6

f(1/2) =(1/2+1)(1/2-2)(2(1/2)-1)

( 3/2)(5/2)(1-1)

8/2

4

f(X) = -3-x+2x²-x³ at X= -2

-3-(-2)+2(-2)^2-(-2)^3

-1+8+8

-1+16

15