Question

1.1. Find the circumcentre of the triangle
whose vertices are (1,0),(-1,2),(3,2)​

Answer 1

Answer:

c is rewtie annsewa of this question

Answer 2

Answer:

Let the coordinates of the vertices of the triangle are A(1,1),B(2,−1) and C(3,2)

Now, Lets find the distance between each of the three points.

We will use the distance formula to find the distance between AB,BC and AC

Thus AB=

(2−1)

2

+(−1−1)

2

=

5

BC=

(3−2)

2

+(2+1)

2

=

10

AC=

(3−1)

2

+(2−1)

2

=

5

NowAB

2

+AC

2

=10=BC

2

Thus it form a right angled triangle, right angled at A.

Now the circumcentre will be the mid-point of the hypotenuse BC.

Thus mid-point of BC is (

2

2+3

,

2

−1+2

)=(

2

5

,

2

1

).

And the circumradius is the half the length of BC

⇒ Circumradius =

2

10