Question

1
1. Find the zero of Polynomial
2x² + 7x - 4 is .​

Answer 1

Answer:

$2 {x}^{2} + 7x - 4 \\ \\ = 2 {x}^{2} + (8 - 1)x - 4 \\ \\ = 2 {x}^{2} + 8x - x - 4 \\ \\ = 2x(x + 4) -1 (x + 4) \\ \\ = (2x - 1)(x + 4) \\ \\ either \: 2x - 1 = 0 \\ \\ = > x = \frac{1}{2} \\ \\ or \: x + 4 = 0 \\ \\ = > x = - 4 \\ \\ so \: zeroes \: of \: the \: polynomial \: are \\ \\ \frac{1}{2} \: and \: - 4$

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Answer 2

Answer:

2x² + 7x - 4

2x² + (8x-1x) - 4

2x² + 8x -x-4

2x(x+4) -1(x+4)

(x+4)(2x-1) =0

x = -4, 1/2

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