Question

1.1
FS
Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height
is 6. Find the ratio of areas of these triangles.
5​

Answer 1

Answer:-

We know in a right angle triangle

$\boxed{\sf Area=\dfrac{1}{2}\times Base\times Height}$

Case-1

• Base=9cm
• Height=5cm

$\\ \rm\longmapsto Area_{(1st\:Triangle)}=\dfrac{1}{2}\times 9\times 5$

$\\ \rm\longmapsto Area_{(1st\:Triangle)}=\dfrac{45}{2}$

$\\ \rm\longmapsto Area_{(1st\:Triangle)}=22.5cm^2$

$\\ \rm\longmapsto Area_{(1st\:Triangle)}=22cm^2(Approx)$

Case-2

• Base=10cm
• Height=6cm

$\\ \rm\longmapsto Area_{(2nd\:Triangle)}=\dfrac{1}{2}\times 10\times 6$

$\\ \rm\longmapsto Area_{(2nd\:Triangle)}=\dfrac{60}{2}$

$\\ \rm\longmapsto Area_{(2nd\:Triangle)}=30cm^2$

Finding ratio:-

$\\ \rm\longmapsto Ratio=\dfrac{22}{30}$

$\\ \rm\longmapsto Ratio=\dfrac{11}{15}$

$\\ \rm\longmapsto Ratio=11:15$