1. (1) How many moles of Mg3(PO4)2 will contain 0.6 moles ofoxygen atoms?
(i) How many moles of (NH4)2 SO4 will contain 0.4 mole of H-atoms?
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(1) 1mole of Mg3(PO4) contains 8 moles of oxgen
so 0.6 moles of oxygen is present in 0.6*1/8=0.075 moles
(2) 1mole (NH4)2SO4 CONTAIN 8 moles of hydrogen so 0.4 moles hydrogen present in 0.4/8=0.05 moles of that cimpound
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