Question

1 + 1 is equal to 1 how solve it in mathematical form

Answer 1

$<b><u>Hello Friend!!!!</u></b>$


$<u><b>Here Is Your Answer</b></u>$



Let a = 1 and b = 1.


$<b>Therefore a = b, by substitution. If two numbers are equal, then their squares are equal, too: a^2 = b^2.</b>$


Now subtract b^2 from both sides (if an equation is true, then if you subtract the same thing from both sides, the result is also a true equation) so a^2 - b^2 = 0.


$<b>Now the lefthand side of the equation is a form known as "the difference of two squares" and can be factored into (a-b)*(a+b).</b>$


If you don't believe me, then try multiplying it out carefully, and you will see that it's correct. So: (a-b)*(a+b) = 0.


$<b>Now if you have an equation, you can divide both sides by the same thing, right? Let's divide by (a-b), so we get: (a-b)*(a+b) / (a-b) = 0/(a-b). </b>$


On the lefthand side, the (a-b)/(a-b) simplifies to 1, right? and the righthand side simplifies to 0, right? So we get: 1*(a+b) = 0, and since 1* anything = that same anything, then we have: (a+b) = 0.


But a = 1 and b = 1, so: 1 + 1 = 0, or 2 = 0. Now let's divide both sides by 2, and we get: 1 = 0.

$<b>Then we add 1 to both sides, and we get what your programming teacher said, namely: 1 + 1 = 1. </b>$


$<b><u>Hope The Above Answer Helped.</b></u>$



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