Question

1 + 1 = ? its not 2 or 11 then what?​

Answer 1

Answer:

1 + 1 = 2

its not 11 not possible to get your answer as 11

Answer 2

Answer:

1

$1 + 1 = 0$

How?

Step-by-step explanation:

Formula

$(x - y) {}^{2} = {x}^{2} - 2 - xy + {y}^{2}$

$1 + 1 = 2 \\ 1 + 1 - 1 = 2 - 1 \\ 1 + 1 - 1 = \sqrt{(2 - 1 {}^{} ) {}^{2} } \\ 1 + 1 - 1 = \sqrt{ {2 {}^{2} -2 \: \:2 - 1 + {1 }^{2} } } \\ 1 + 1 - 1 = \sqrt{4 - 4 + 1} \\ 1 + 1 - 1 = \sqrt{1} \\ 1 + 1 - 1 = \sqrt{( - 1) {}^{2} } \\ 1 + 1 - 1 = - 1 \\ 1 + 1 = 0$

Now Your Question Is How Did You Proof That?

In my calculation You can have a look carefully where did I didn't follow the rules of Mathematics...

This is pretty funny be sure

THANK YOU DEAR.....❤