1. 1 L mixture of CO and Co, gases were passed
over hot coke and final volume of the mixture became
1200 mL. Volume of CO gas in the initial mixture was
(1) 800 mL
(2) 200 ml
(3) 400 ml
(4) 600 mL
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The total volume of the mixture = 1 L Let the volume of CO in the mixture = x L The volume of CO2 in the mixture = (1- x) L On passing mixture through a tube containing red hot charcoal. CO2 is completely reduced to CO. Thus, the product obtained is only CO .Thus, the volume of CO in mixture = 0.4 L The volume of CO2 in mixture = (1 - 0.4) L = 0.6 L=600ml.
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