Question

1.1 moles of A are mixed with 2.2 moles of B and the mixture is kept in one litre flask till equilibrium is reached A+2B==2C+D At equilibrium 0.2 moles of C are formed. The equilibrium constant for reaction is​

Answer 1

Answer:

aa−x

A

+

bb−2x

2B

⇌

02x

2C

+

0x

D

Given, 2x=0.2, Also, a=1.1

x=0.1b=2.2

∴K

c

=

(a−x)(b−2x)

2

4x

3

=

(1.1−0.1)(2.2−0.2)

2

4×(0.1)

3

=0.001