Math, asked by nikhilaghanagam, 9 months ago

1/1+root2+1/root2+root3+1+root3+root4​

Answers

Answered by somyavats1515
0

Hi mate!

What's up?

Answer:

1 + R2 + 1R2 + R3 + 1 + R3 + R4

= 2 + 2R2 + 2R3 + R4

It can not be further simplified.  So this is the answer.

Actually R stands for root as I couldn't use the symbol.

Answered by maruganinandini917
0

Answer:

if1/1+√2+1/√2+√3+1+√3+√4=0

1/√2(1/1+√2+1/√2+√3+1+√3+√4)=1/2(0)

1/√2+√2/√2+√2/√2.√2+√3/√2+1/√2+√3/√2+√4/√2=0

1/√2+1+1/√2+√3/√2+1/√2+√3/√2+2/√2=0

3/√2+2/√2+2√3/√2=-1

5+2√3=-2

square on both sides

then we get

33-203

I don't know right or wrong

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