Math, asked by Nikhil8037, 1 year ago

(1/1+sin^2A) + (1/1+cos^2A) + (1/1+sec^2A) + (1/1+cosec^2A)

Answers

Answered by spiderman2019
2

Answer:

2

Step-by-step explanation:

(1/1+Sin²A) + (1/1+Cos²A) + [1/1+(1/Cos²A)] + [1/1+(1/Sin²A)]

= (1/1+Sin²A) + (1/1+Cos²A) + (Cos²A/1+Cos²A) + (Sin²A/1+Sin²A)

= (1+Sin²A) / (1+Sin²A) + (1+Cos²A) / (1+Cos²A)

= 1 + 1

= 2

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