Question

1/1+ sinA + 1/1- sin A = 2 sec^2 A​

Answer 1

Answer:

LHS

1/(1+sinA)+1/(1-sin A)

=(1-sin A)+(1+sinA)/(1+sinA)(1-sinA)

=(1-sinA+1+sinA)/(1-sin^2A)

=2/cos^2A

=2sec^2A

=RHS