Question

1/1-sinA + 1/1+sinA = 2sec 2 A

Answer 1

this is equal to RHS and hence ur identity is clear......

hope it will be helpful

Answer 2

1/(1-sinθ) +1/(1+sinA)
[1+sinA +1-sinA]/(1-sin²A)
2/cos²A
2*1/cos²A
2*sec²A